W(x)=3x^2+13x-30

Solution for W(x)=3x^2+13x-30 equation:

(W)=3W^2+13W-30

We move all terms to the left:

(W)-(3W^2+13W-30)=0

We get rid of parentheses

-3W^2+W-13W+30=0

We add all the numbers together, and all the variables

-3W^2-12W+30=0

a = -3; b = -12; c = +30;
Δ = b2-4ac
Δ = -122-4·(-3)·30
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{14}}{2*-3}=\frac{12-6\sqrt{14}}{-6}
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{14}}{2*-3}=\frac{12+6\sqrt{14}}{-6}
$